C++ help ekak...ooone ayyala

[haarshlife]

Write a C ++ program to display the following output using nested loops.
[0 0 0]
[0 0 1]
[0 0 2]
[0 I 0]
[0 1 1]
[0 1 2]
[2 2 2]

 

[haarshlife]

meka ayyala nested FOR loop ekin karanna puluwanne...

 

[haarshlife]

#include<iostream>
using namespace std;
int main()
{
(methana initialize karanne kohomada )

 

[scoobyy]

anthima peliya sureda hariyata liwwa kiyala??

 

[achintha]

ahh macho meka hodada/ mokatada ban loop danna gihin nikan amaruwe watenne... mehema dapan

#include<iostream>
using namespace std;
int main()
{
cout<<"[0 0 0]\n[0 0 1]\n[0 0 2]\n[0 I 0]\n[0 1 1]\n[0 1 2]\n[2 2 2]";
}

 

[scoobyy]

ahh macho meka hodada/ mokatada ban loop danna gihin nikan amaruwe watenne... mehema dapan

meka nested loopsds ban he he

 

[haarshlife]

ahh macho meka hodada/ mokatada ban loop danna gihin nikan amaruwe watenne... mehema dapan

happe oya mokakda bun...

 

[dakshina11]

machan ubata me loop eka sure da?????????

 

[Jack_Sparrow]

#include<iostream>
using namespace std;
int main()
{

for(int j=0;j<3;j++)
{
for(int i=0;i<3;i++)
{
for(int r=0;r<3;r++)
{

cout<<"["<<j<<","<<i<<","<<r<<"]"<<endl;

}
r=0;
}
i=0;
}
return 0;
}


balahang mehema
meeka sure nee mama den nikan hitala gehuwe

 

[scoobyy]

for(int i=0; i<3; i=i+2){
for (int j=0; j<3; J++){
for (int k=0; k<3; k++){
if (i==2 && j==2 && k==1){
k++;
cout<<i<<j<<k; break;
}
cout<<i<<j<<k; endl
}
}
}



Meka wadada balapan macho

 

[scoobyy]

#include<iostream>
using namespace std;
int main()
{

for(int j=0;j<3;j++)
{
for(int i=0;i<3;i++)
{
for(int r=0;r<3;r++)
{

cout<<"["<<j<<","<<i<<","<<r<<"]"<<endl;

}
r=0;
}
i=0;
}
return 0;
}


balahang mehema
meeka sure nee mama den nikan hitala gehuwe

Ai r and i 0 karanne??

 

[Jack_Sparrow]

Ai r and i 0 karanne??

r right hand side eeke 1st digit 1
i right indan next eka thn left eke tiyana first eka j


meeeke r =3 unama ethulema tiyana loop eken paninawa bt ethakota [0,0,1] and [0,0,2] display outer loop ekata awama i =1 wenawa thn mama r=0 kala thn ayeth r tiyana loop eka weda ohoma ayeth 3 unama ayeth i tiyana loop ekakain 1kin wedi wenawa ayeth r =0 wenawa ohoma ohoma wenawa

 

[scoobyy]

r right hand side eeke 1st digit 1
i right indan next eka thn left eke tiyana first eka j


meeeke r =3 unama ethulema tiyana loop eken paninawa bt ethakota [0,0,1] and [0,0,2] display outer loop ekata awama i =1 wenawa thn mama r=0 kala thn ayeth r tiyana loop eka weda ohoma ayeth 3 unama ayeth i tiyana loop ekakain 1kin wedi wenawa ayeth r =0 wenawa ohoma ohoma wenawa

itin ban loop eken loop wenna patan ganakota apahu 0 wenawane...

 

[scoobyy]

r right hand side eeke 1st digit 1
i right indan next eka thn left eke tiyana first eka j


meeeke r =3 unama ethulema tiyana loop eken paninawa bt ethakota [0,0,1] and [0,0,2] display outer loop ekata awama i =1 wenawa thn mama r=0 kala thn ayeth r tiyana loop eka weda ohoma ayeth 3 unama ayeth i tiyana loop ekakain 1kin wedi wenawa ayeth r =0 wenawa ohoma ohoma wenawa

Umbe me thiyene loop eke hatiyata
[1,1,1]
[1,1,2]

wage ewath print wenawa neda balapn......

 

[Jack_Sparrow]

itin ban loop eken loop wenna patan ganakota apahu 0 wenawane...

nee machan mehema neee

ethulama tiyana loop 1 ganin

thn eeeke r = 3 unama ee loop eka newe eeka nawatinawa thn eekata uda tiyana loop eka


eeke mama r=0 karala tiyanawa dekkada?

eee wena kota 2nd tiyana loop eke 1k gihin

ethakota eeke i =1 wenawa den ayeth ethulema tiyana loop eka weda mokada r=0 nisa

thn ayeth r=3 unama ayeth yanawa deweni loop ekata ethakota ayeth i=2 wenawa r=0 wenawa r8 ?

thn ayeth ethulema loop eka weda thn ayeth eliyata awama i=3 wenawa ethakota 2md loop eka hitinawa

thn yanawa udama tiyana loop ekata thn eekedi i=0 bt e wenakotatah udama loop eke j ekakain wedi wenawa

e kiyanne j=1 wenawa

thn ayeth meda loop eka weda

meeeka ohommama 222 wedila loop tunama nawatinawa

 

[Jack_Sparrow]

Umbe me thiyene loop eke hatiyata
[1,1,1]
[1,1,2]

wage ewath print wenawa neda balapn......

maala ehemada

hehe neene ban mulinma mama loop wala j i r 0 walata assign kalaneee

thn mulinma increament 1 wenne r ge

thn

[0,0,0]
[0,0,1]
[0,0,2]


eeta passe eliye loop ekata awama

r=0 i ekakin wedi wenawa

thn ayeth ethule loop eka weda

[0,1,0]
[0,1,1]
[0,1,2]

 

[dakshina11]

meka balapan

#include<iostream>
using namespace std;
int main()
{
for(int k=0;k<=2;k++)
{
for(int j=0;j<=2;j++)
{
for(int i=0;i<=2;i++)
{
cout<<"["<<k<<" "<<j<<" "<<i<<"]"<<endl;
}
}
}
}



machan mekath poddak balapan.