Can you solve this?...

[peacockone]

x( x^2 + 3 ) = 4x+6 , can you find x?

 

[peacockone]

anybody?

 

[ijay]

 

[NEMISIS]

https://www.wolframalpha.com/input/?i=x(+x^2+++3+)+=+4x+6

 

[chathurachami]

X=2

 

[peacockone]

https://www.wolframalpha.com/input/?i=x(+x^2+++3+)+=+4x+6

X=2

yes machan, i have already tried and got the answer x=2, but how, do you know the steps?...

 

[ThimalM™]

x^3 - x-6= 0
X^3-4X+3X-6 = 0
x(x^2 - 4)+3(x-2)=0
(x-2){x+2x+3} = 0
real valued answer = 2

 

[labu gediya]

x( x^2 + 3 ) = 4x+6 , can you find x?

ඔය තියෙන්නේ බං තද දුඹුරු පාටින්...X

 

[රඹා]

ඔය තියෙන්නේ බං තද දුඹුරු පාටින්...X

 

[peacockone]

ඔය තියෙන්නේ බං තද දුඹුරු පාටින්...X

Heh heh heh....

 

[peacockone]

x^3 - x-6= 0
X^3-4X+3X-6 = 0
x(x^2 - 4)+3(x-2)=0
(x-2){x+2x+3} = 0
real valued answer = 2

Superb machan...but i couldn't understand the way you did the 4th line

 

[chashikajw]

!!

mchn uba a/l krnwanam me wge awa wisadanna a/l wala danata tyenne sadaka prameya withri. parana sylabus ake nam kramayk tynwa. uba a/l kiyala mn hithla aken wisadana widiya kynnm.

f(x) = x^3 - x - 6
meke api hynna one x ta aka aka agayan adesha kra kra f(x) shrithaya 0 wena sadaka. athkota apita enawaneh f(2) wita srithaya 0 wenawaneh. ethkota apita enawa (x-2) kiyanne f(x) hi sadakayak kiyala.

ita passe one nam thwa agayan dada sadaka hynna plwn. eth hodama wade dan labuna sadaken api f(x) wa beduwama apita wargaja prakashnyk enawane.ethkota apita lesi ake sadaka hoyamna 1. a nisa ahema bedamu.

(x^3 - x - 6) /(x-2) =x^2 +2x + 3
dan apita f(x) wa mehema liyaganna puluwn
f(x) = x^3 - x - 6 = (x-2)(x^2 +2x + 3)
dan apita anith wargaja srithaye sadaka hynna plwn. ita kalin ake sadaka tynwda blnna. mkada ake delta X 0ta wada adu unoth ake sadaka kadenne nane.
(x^2 +2x + 3) mehi delta x= 4-4*3= -8. a nisa ake sadaka kadenne na.
a nisa f(x)=(x-2)(x^2 +2x + 3)

(x-2)(x^2 +2x + 3)=0 ema nisa x sadaha sankirna nowana awayawa enne 2 withri.

 

[coefficient]

Superb machan...but i couldn't understand the way you did the 4th line

x(x^2 - 4)+3(x-2)
x(x^2 - 2^2) +3(x-2)
x[(x-2)(x+2)] +3(x-2)
(x-2)[x(x+2) + 3 ]

 

[peacockone]

mchn uba a/l krnwanam me wge awa wisadanna a/l wala danata tyenne sadaka prameya withri. parana sylabus ake nam kramayk tynwa. uba a/l kiyala mn hithla aken wisadana widiya kynnm.

f(x) = x^3 - x - 6
meke api hynna one x ta aka aka agayan adesha kra kra f(x) shrithaya 0 wena sadaka. athkota apita enawaneh f(2) wita srithaya 0 wenawaneh. ethkota apita enawa (x-2) kiyanne f(x) hi sadakayak kiyala.

ita passe one nam thwa agayan dada sadaka hynna plwn. eth hodama wade dan labuna sadaken api f(x) wa beduwama apita wargaja prakashnyk enawane.ethkota apita lesi ake sadaka hoyamna 1. a nisa ahema bedamu.

(x^3 - x - 6) /(x-2) =x^2 +2x + 3
dan apita f(x) wa mehema liyaganna puluwn
f(x) = x^3 - x - 6 = (x-2)(x^2 +2x + 3)
dan apita anith wargaja srithaye sadaka hynna plwn. ita kalin ake sadaka tynwda blnna. mkada ake delta X 0ta wada adu unoth ake sadaka kadenne nane.
(x^2 +2x + 3) mehi delta x= 4-4*3= -8. a nisa ake sadaka kadenne na.
a nisa f(x)=(x-2)(x^2 +2x + 3)

(x-2)(x^2 +2x + 3)=0 ema nisa x sadaha sankirna nowana awayawa enne 2 withri.

x(x^2 - 4)+3(x-2)
x(x^2 - 2^2) +3(x-2)
x[(x-2)(x+2)] +3(x-2)
(x-2)[x(x+2) + 3 ]

Thanks buddy...

 

[W33R3]

ඔය තියෙන්නේ බං තද දුඹුරු පාටින්...X

උබනම් ..... එක්කෝ ඕනේ නෑ.