The generalized solution you can detect a coin within n weighings is (3^n − 1)/2
So for 13 coins the problem can be solved in 3 weighings (n=3)
Hint - First weigh 4 & 4 (that's 8) and keep 5 aside on the table.
If scales balance then the fake coin is on the table
If the scales don't balance then the fake is on the scales...
Depatta balance karana tharadiyakin nam puluwan electronic ekakin nam ba 3 parakin. electronic ekakin4 parak wath yanwa .
4 bagin depattata dala balance karanna. depatta balance nam e gedi 8 equal. equal une nathnam , bara wadi paththe gedi 4 depatatta dala gedi 2 ka 2ka ekenuth bara wadi patte gedi deka depathta dala hoyanna puluwan by 3 steps
hadissyewath uda 4 4dapu eka balance nam ithuru 5 ne tiyene bara wenas eka. dan e 5n 4 k aran depattata dala 2 2 bara equal da balanna. equal nam ara ithuru gediya tama bara wenas. me 2ka 2ka dapu eke eka pattak bara wadi nam e patte gedi deka ayth dala balanna 1 1 depattata.... Me wage ganan nam ithin Dollar walin wadi karana Rupiyal walin answer dena lapayaunath hadai