Karnaugh Maps

[pizzu puza]

No need to draw 7 points. because all 1s are included this two points. so why we complex our output. Kanaugh maps purpose is simplify logic.

You haven't included 11 and 13

 

[සුදු මහත්තයා]

You haven't included 11 and 13

using 1 seven segment you cannot display 11 and 13. so it didn't care.

 

[070348K]

Look at this pdf, it has a solved minimized 4-bit input prime detector.

http://www.engr.usask.ca/classes/EE/232/EE232_2011/notes/04_combinational logic_part2.pdf

Use an LED for giving the output (they say to convert in to a circuit ). Don't need to use a CCD.

 

[pizzu puza]

using 1 seven segment you cannot display 11 and 13. so it didn't care.

Machan the question doesn't ask for a seven segment display.
Only to identify whether a prime between 0-15 is present or not. So, there are 7 primes. We have to identify all 7 and give an output 1 if any of them is present.

 

[සුදු මහත්තයා]

Machan the question doesn't ask for a seven segment display.
Only to identify whether a prime between 0-15 is present or not. So, there are 7 primes. We have to identify all 7 and give an output 1 if any of them is present.

oooops, sorry. I think she can correct it.

thanks for correction. normally this type of questions come with SSD. so I didn't read it carefully.

 

[pizzu puza]

oooops, sorry. I think she can correct it.

thanks for correction. normally this type of questions come with SSD. so I didn't read it carefully.

 

[jamiezue]

karnaugh maps අඳින්න මෙතනින් ඉගෙන ගන්න...මමත් ඉගෙන ගත්තෙ මෙතනින්,,,,,

http://www.allaboutcircuits.com/vol_4/chpt_8/1.html

 

[actinide]

Look at this pdf, it has a solved minimized 4-bit input prime detector.

http://www.engr.usask.ca/classes/EE/232/EE232_2011/notes/04_combinational logic_part2.pdf

Use an LED for giving the output (they say to convert in to a circuit ). Don't need to use a CCD.

here u can find the answer. but remember 1 is not a prime number.
so u hav to correct it.

 

[pizzu puza]

here u can find the answer. but remember 1 is not a prime number.
so u hav to correct it.

Yes. But what to do is the question itself states as such, as in this case.. Just have to go with the question.

 

[actinide]

Yes. But what to do is the question itself states as such, as in this case.. Just have to go with the question.

oops...

 

[kterulz]

බම්ප් ...

 

[මහ නිළමේ]

 

[jamiezue]

A^D +ABC^D +AB^CD =answer

^= bar

 

[kumu123]

read this

http://en.wikipedia.org/wiki/Karnaugh_map

 

[070348K]

Yes. But what to do is the question itself states as such, as in this case.. Just have to go with the question.

I read question again and again .... it's says to come up with a standard 4-bit prime detector. That's it.

 

[nagaya]

ah meka podi seen 1k ne

 

[SuduuNangiya]

I can do, but busy in the week end, will answer you in monday.
(how much you pay . . . hi . . hi . . )

 

[subspace]

A^D +ABC^D +AB^CD =answer

^= bar

මේක හරි.

(වෙන එක්කෙනෙක් කරාම මැදට පැනල ලකුනු දාගන්න නෙවේ, මේකේ තියෙන උත්තර වලින් මොකක්ද තෝරාගන්නේ කියල confused නම්)

 

[||~R_girl~||]

Hey guys thank you soo much for helping... means a lot

 

[||~R_girl~||]

ohhh crap thats not it.. getting the right answer aint enough... :S they want me to do a presentation explaining how i got the answer...
i know how to draw the karnaugh map from the truth table, deriving the boolean expression and circuit and all the rest of it.... but what i dont get is the Truth table... how did you guys get that Y output? how do we know if its true or not?