Network Subnetting Help

[isurutmv]

mcn mage assignment ekakata network ekak design karanna thiyenawa meke branches 3 k thiyenawa eka branch ekaka 500 pc thiyenawa anith deke 40 pc gaane thiyenawa mama meke Ip gatte 192.168.0.0/23

mata thiyena awula me branches 3 ta wenama subnet hadanne kohomada kiyala danna kenek upadesak kotagena yamalla

 

[Franklin EK]

..B U M P..​

 

[ipyaka]

Branch with 500 Hosts
NW = 192.168.0.0/23
Mask = 255.255.254.0
Hosts = 510
NW Address = 192.168.0.0
Broadcast Address = 192.168.1.255
HOST IP Range = 192.168.0.1 to 192.168.1.254

Branch with 40 Hosts
NW = 192.168.2.0/26
Mask = 255.255.255.192
Hosts = 62
NW Address = 192.168.2.0
Broadcast Address = 192.168.2.63
HOST IP Range = 192.168.2.1 to 192.168.2.62

Branch with 40 Hosts
NW = 192.168.2.64/26
Mask = 255.255.255.192
Hosts = 62
NW Address = 192.168.2.64
Broadcast Address = 192.168.2.127
HOST IP Range = 192.168.2.65 to 192.168.2.126

 

[isurutmv]

Branch with 500 Hosts
NW = 192.168.0.0/23
Mask = 255.255.254.0
Hosts = 510
NW Address = 192.168.0.0
Broadcast Address = 192.168.1.255
HOST IP Range = 192.168.0.1 to 192.168.1.254

Branch with 40 Hosts
NW = 192.168.2.0/26
Mask = 255.255.255.192
Hosts = 62
NW Address = 192.168.2.0
Broadcast Address = 192.168.2.63
HOST IP Range = 192.168.2.1 to 192.168.2.62

Branch with 40 Hosts
NW = 192.168.2.64/26
Mask = 255.255.255.192
Hosts = 62
NW Address = 192.168.2.64
Broadcast Address = 192.168.2.127
HOST IP Range = 192.168.2.65 to 192.168.2.126

thank you mcn meka gattu widihath explain karanna puluwannam loku udawuwak

 

[genius_EK]

VLSM

 

[lalindutj]

VLSM

CIDR 23 eke 580 hosts puluwanda bn

 

[genius_EK]

CIDR 23 eke 580 hosts puluwanda bn

baa /23 max IP's 512 (510 host)
VLSM walada subnet mask eka variable eka wenas karanne ekaii
max 512 passe subnet eka next segment eken ganne like "ipyaka"

 

[ipyaka]

thank you mcn meka gattu widihath explain karanna puluwannam loku udawuwak

Its VLSM ( Veriable Lenght Subnet Masking )

IP Blocks are comimng in Factors of 2

2 = 2^1 = /31 (32-1) = 255.255.255.254
4 = 2^2 = /32 (32-2) = 255.255.255.252
8 = 2^3 = /29 (32-3) = 255.255.255.248
16 = 2^4 = /28 (32-4) = 255.255.255.240
32 = 2^5 = /27 (32-5) = 255.255.255.224
64 = 2^6 = /26 (32-6) = 255.255.255.192
128 = 2^7 = /25 (32-7) = 255.255.255.128
256 = 2^8 = /24 (32-8) = 255.255.255.0
512 = 2^9 = /23 (32-9) = 255.255.254.0
1024 = 2^10 = /22 (32-10) = 255.255.252.0


So if you need 500 host in one branch , you have to take 512 host range .
192.168.0.0/23

if you need 40 hosts ...You need to get a 64 block , But you can not get it from 192.168.0.0/23 since its utilized for branch 1 therefore you have to get the next block 192.168.2.0 , it can be divided into 4 nos of 64 blocks from that IP range 192.168.2.0/26 , 192.168.2.64/26 ,192.168.2.128/26 ,192.168.2.192/26

hope you get an idea about it

 

[genius_EK]

Its VLSM ( Veriable Lenght Subnet Masking )

IP Blocks are comimng in Factors of 2

2 = 2^1 = /31 (32-1) = 255.255.255.254
4 = 2^2 = /32 (32-2) = 255.255.255.252
8 = 2^3 = /29 (32-3) = 255.255.255.248
16 = 2^4 = /28 (32-4) = 255.255.255.240
32 = 2^5 = /27 (32-5) = 255.255.255.224
64 = 2^6 = /26 (32-6) = 255.255.255.192
128 = 2^7 = /25 (32-7) = 255.255.255.128
256 = 2^8 = /24 (32-8) = 255.255.255.0
512 = 2^9 = /23 (32-9) = 255.255.254.0
1024 = 2^10 = /22 (32-10) = 255.255.252.0


So if you need 500 host in one branch , you have to take 512 host range .
192.168.0.0/23

if you need 40 hosts ...You need to get a 64 block , But you can not get it from 192.168.0.0/23 since its utilized for branch 1 therefore you have to get the next block 192.168.2.0 , it can be divided into 4 nos of 64 blocks from that IP range 192.168.2.0/26 , 192.168.2.64/26 ,192.168.2.128/26 ,192.168.2.192/26

hope you get an idea about it

lol kalekin subletting walata basse

192.168.0.0 /23
mehema subnet ganna puluwanda ban oka class c nee /24 after 24 bit nee subnet bits assign karanna puluwan ehema ekakata /23 kiyala ganna puluwanda ban

 

[ipyaka]

lol kalekin subletting walata basse

192.168.0.0 /23
mehema subnet ganna puluwanda ban oka class c nee /24 after 24 bit nee subnet bits assign karanna puluwan ehema ekakata /23 kiyala ganna puluwanda ban

Yes you can

 

[genius_EK]

Yes you can

meka balahan

original network eka

192.168.0.0 /23
192.168.00000000.00000000
255.255.11111110.00000000 (Mask)

dan ban oya network eka kochcra subnet karath right (->) oya digit 9 nee gama gahanna thiyenne,


increment :2

so 1st subnet ,

192.168.0.0 - 192.168.1.255

meka awlak naa but

2nd subnet,

192.168.2.0 - 192.168.3.255

host,

192.168.2.1 ---- 192.168.00000010.00000001
mask------------255.255.00000000.00000000

dan oka balanna 2nd octet eka 2 wenakota <- original network eke mask eken ekak panala ee kianne apita play karanna puluwan 9 digit but meka 10 digit wela.


oka nikan ganana wage hadagena hadagena yanna puluwan eth mee case eka enawa nee

 

[ipyaka]

meka balahan

original network eka

192.168.0.0 /23
192.168.00000000.00000000
255.255.11111110.00000000 (Mask)

dan ban oya network eka kochcra subnet karath right (->) oya digit 9 nee gama gahanna thiyenne,


increment :2

so 1st subnet ,

192.168.0.0 - 192.168.1.255

meka awlak naa but

2nd subnet,

192.168.2.0 - 192.168.3.255

host,

192.168.2.1 ---- 192.168.00000010.00000001
mask------------255.255.00000000.00000000

dan oka balanna 2nd octet eka 2 wenakota <- original network eke mask eken ekak panala ee kianne apita play karanna puluwan 9 digit but meka 10 digit wela.


oka nikan ganana wage hadagena hadagena yanna puluwan eth mee case eka enawa nee

192.168.0.0 /23
192.168.00000000.00000000
255.255.11111110.00000000 (Mask)


192.168.2.0 /23
192.168.00000010.00000000
255.255.11111110.00000000 (Mask)

You got it confused machan , Let me explain the second senario
/23 = 255.255.254.0 = 11111111.11111111.11111110.00000000
192.168.2.0 in to binary = 11000000.10101000.00000010 .00000000

So
Network = 11000000.10101000.00000010.00000000
Mask = 11111111.11111111.11111110.00000000

In Mask '1' means you can not change the bit in Network address , '0 'means that bit can change

That means you can not change this part 11000000.10101000.0000001

Then the first address will be 11000000.10101000.00000010.00000001 = 192.168.2.1 and the last address will be 11000000.10101000.00000011.11111111 = 192.168.3.255