Physics Dannawada

nrjayasinghe

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  • Mar 7, 2007
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    මචංලා... මට මේ ගාන හදල දීපන්
    t=0 දී ස්කණ්ධය m වූ බෝලයක් u වේගයෙන් සිරස්ව ඉහලට විසිකර t=2s ට පසු ස්කන්ධය 2m වන තවත් බෝලයක් එම ස්ථානයෙන්ම එම වේගයෙන්ම ඉහලට විසි කරන ලදී. බෝල 2 ගැටීමට ගතවන කාලය සොයන්න
     

    cnf271

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  • Jun 11, 2011
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    machng oka umbata prawage kala prastharayakin lesiyenma karanna puluwanne!
    ekama stahanaka awastha 2ma adinna!

    nethang umbata puluwang chalitha samikarana walata yanna!
     

    nrjayasinghe

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  • Mar 7, 2007
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    machng oka umbata prawage kala prastharayakin lesiyenma karanna puluwanne!
    ekama stahanaka awastha 2ma adinna!

    nethang umbata puluwang chalitha samikarana walata yanna!

    Pravega kala prastharenuth puluwan neda, Chalitha sameekarana dana eka poddak petaluna machan
     

    cnf271

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    machng but apita kiyapu widihata oke awastha 3k thiyenawa (podak gane balapan mehemada kiyala) nethang umbata awastha 3nma hadanna wenawa!

    1). 1 bolaya uda yanaw wita dewana bolaya pasupasin gos wadei!

    2).1 bolaya ihalama laskshayata gos pravegaya V=0 wita 2wana bola gatima

    3).1 bolaya ihalama lakshayata gos newath paminimedi 2 bolaya ha gatima!
     

    nrjayasinghe

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    awlak neha bt mage kalpanawa enne nathe skandaya gena!!
    umbata onenang f=ma dala a=g(10) nd m =m/2m kiyala awasttha dekakata danna!
    prawega kala prasthara man hithanne lesi! :yes:

    Prawega kala prastharayen behe machan, Samanthara Reka dekak enne, Ewa cross wenne nehe ne :no:
     

    Sparxrc

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    Dec 30, 2007
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    InUrHeart
    machng but apita kiyapu widihata oke awastha 3k thiyenawa (podak gane balapan mehemada kiyala) nethang umbata awastha 3nma hadanna wenawa!

    1). 1 bolaya uda yanaw wita dewana bolaya pasupasin gos wadei!

    2).1 bolaya ihalama laskshayata gos pravegaya V=0 wita 2wana bola gatima

    3).1 bolaya ihalama lakshayata gos newath paminimedi 2 bolaya ha gatima!

    ow meh 3 gana wistharayak nadda deela ?
     
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    cnf271

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    machng ithink answer is 2v+gt
    2g
    ado prawega kala prashatre nam adinna bahne methana!
    pravega kala prasthgare machng! ahh adinne nathiwa umbata wisthara karanna amarui!
    mulinma umba mekata
    1 bolaya A
    2 bolaya B

    V(A,B)= pahalata italaya g (g = guruthwaga tharanayata)
     

    cnf271

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    mehemai
    thrapisiyame wargapalaya = rigukonasraye wargapalaya
    (v+v1)T = gT.t
    2
    V+V-gt =gt
    2

    2v-gT = gt
    2
    emanisa
    t= 2V-gt
    2g

    i think so machng!!! doiyathmathi!!
    ]meka wisthara karanna amarui prawege kala prasthare umbata pennale nathuwa!! all da bst
     
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    lak3a1

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    Nov 15, 2011
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    Applying s=ut+0.5at^2

    for 1st ball (vertically upward direction)
    h=u(t+2) - 0.5g(t+2)^2 ---------------(1)

    for 2nd ball (vertically upward direction)
    h=ut - 0.5gt^2 ---------------(2)

    (1)-(2) gives

    t = u/g -1 (time taken to for the collision after launching the 2nd ball)

    or

    t' = u/g + 1 (time taken to for the collision after launching the 1st ball)


    :) harida danne na. waradi nam sorry.....