Try This Programming Question

[rclakmal]

Hey Guys here a little bit hard(little bit) question !! I found it on Internet !! And I got the answer !! Give it a try .if u can find out the answer it will give u the same happiness that i got !!

Post ur answer .....then i will give the correct one and my code

Find the largest product of five consecutive digits in the 1000-digit number.Below the number is given!

73167176531330624919225119674426574742355349194934
 96983520312774506326239578318016984801869478851843
 85861560789112949495459501737958331952853208805511
 12540698747158523863050715693290963295227443043557
 66896648950445244523161731856403098711121722383113
 62229893423380308135336276614282806444486645238749
 30358907296290491560440772390713810515859307960866
 70172427121883998797908792274921901699720888093776
 65727333001053367881220235421809751254540594752243
 52584907711670556013604839586446706324415722155397
 53697817977846174064955149290862569321978468622482
 83972241375657056057490261407972968652414535100474
 82166370484403199890008895243450658541227588666881
 16427171479924442928230863465674813919123162824586
 17866458359124566529476545682848912883142607690042
 24219022671055626321111109370544217506941658960408
 07198403850962455444362981230987879927244284909188
 84580156166097919133875499200524063689912560717606
 05886116467109405077541002256983155200055935729725
 71636269561882670428252483600823257530420752963450

try it !!!!!!!! For more codes go to below thread

http://elakiri.com/forum/showthread.php?p=5955033#post5955033

 

[pjayampathi]

[
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Euler
{
class Problem48 : IProblemBase
{

//The series, 1^(1) + 2^(2) + 3^(3) + ... + 10^(10) = 10405071317.

//Find the last ten digits of the series, 1^(1) + 2^(2) + 3^(3) + ... + 1000^(1000).

public Problem48()
{
}

public string GetAnswer()
{
int limit = 1000;
string result = string.Empty;

for (int i = 1; i <= limit; i++)
{
result = Util.BigAdd(result, Util.BigPow2(i, i));
}
return result.Substring(result.Length - 10, 10);
}

}
}

/QUOTE]

not my code.

 

[Myth]

....

 

[pjayampathi]

ooka sinhalen kiyanawaa nam mama code karannam...

 

[Mihindu_Gajaba]

damn whats that

 

[Mihindu_Gajaba]

ooka sinhalen kiyanawaa nam mama code karannam...

he he ekanam atha

 

[1118lakmalkumara]

Matanam Melo deyak therenne nahe monawada me Kiyala diyallako apitath

 

[rclakmal]

ooka sinhalen kiyanawaa nam mama code karannam...

Then whose code??????
did the question confused u ?? hope u did get the problem.!!!!!

 

[pjayampathi]

Then whose code??????
did the question confused u ?? hope u did get the problem.!!!!!

that is the point.. I didn't get the problem...

 

[rclakmal]

Matanam Melo deyak therenne nahe monawada me Kiyala diyallako apitath

Machan meke ahanne dan oya deela thiyena diga no eka thiyenwane ....eke onema thnaka eka peliyata thiyena ( eka digata) digits 5 k aran wadikaloth (multiply) ganna puluwan wadima agaya keeyda kiyala ahanne ..........

dan as an example 1st row eke 5th digit eka 7 ne ..eetapasse thiyena digits piliwelin 1,7,6,5 oki ........

oya 5 wadikaloth answer eka =7*1*7*6*5=1470

oya wage consecutive numbers 5k wadikrala ganna puluwan wadima agaya ahanne !!!!!

Hope u got it !!!!!

 

[1118lakmalkumara]

Machan meke ahanne dan oya deela thiyena diga no eka thiyenwane ....eke onema thnaka eka peliyata thiyena ( eka digata) digits 5 k aran wadikaloth (multiply) ganna puluwan wadima agaya keeyda kiyala ahanne ..........

dan as an example 1st row eke 5th digit eka 7 ne ..eetapasse thiyena digits piliwelin 1,7,6,5 oki ........

oya 5 wadikaloth answer eka =7*1*7*6*5=1470

oya wage consecutive numbers 5k wadikrala ganna puluwan wadima agaya ahanne !!!!!

Hope u got it !!!!!

I got but
mole wehesanna one sahenna ekata

 

[IceCool123]

Answer is from Python

file = open('number.txt', 'r')

a = [int(line) for line in file]
b = str(sum(a))
print b[:5]

file.close()

number.txt contained the digit lines that you have provided.

Answer is : 10641

 

[rclakmal]

Answer is from Python

file = open('number.txt', 'r')

a = [int(line) for line in file]
b = str(sum(a))
print b[:5]

file.close()

number.txt contained the digit lines that you have provided.

Answer is : 10641

hmm sry dude answer is wrong !!!! But appreciate ur try !!!!! shall I give u the correct answer to try it?or will u give another try without the answer !
Hint
Here u have to consider all the occurrences. as i mentioned above u can pick 5 numbers from anywhere ......not 1 to 5 ,5 to 10 ,10 to 15
It can be 6 to 11 ,13 to 18 like wise

I think that is why u have got a wrong answer !

 

[rclakmal]

And of course ,I also used a file to store this data !!! Its the easier method !

 

[rclakmal]

*** bumped***

 

[rclakmal]

Ko kawruth try kale nadda??????????