What is the squre root of -1

[nagaya]

i^2 = sqrt((-1)*(-1)) (e.g. sqrt(2)*sqrt(2) = sqrt(2*2) )

this is wrong... think this with +,- values...

i.e. sqrt(4) = 2 is wrong it should be +or- 2

nope sqrt(4) = 2 is right
you only get + & - when solving a equation becoz of factors (warga 2kaka antharaya)

for the problem in the thread;
[sqrt(-1)]^-2=-1 not +1,so it can't be done like this
man kalin kyanna ghn poddk aul una,kalin post eka ignore karanna