දවසේ පැනය. තමන් කැමති ඕනැම දෙයකින් කල හැක

[HAneo]

කැමති ඕනෙම ප්රෝග්‍රමින්ග් ලන්වේජ් එකක් තෝරා ගන්න. අලුත් ලන්වේජ් වලින් කරලා දාපල්ලා අනින් උනුත් ඉන්ස්පයර් ද මොකක්ද එක වෙන්න. තේරෙන්නේ නැති උන් අහපල්ලා ඕක සිංහලෙන් කියල දෙයි කව්රු හරි​

 

[CorD SaC]

Bump

Updated:

public static class Program {
  static void Main(string[] args) {
    int B = 1, A = 1, L = 2, O = 2, N = 1, count = 0;
    //var s = "BAOOLLNNOLOLGBAX";
    var s = "BAONXXOLL";

    while (s.Count(x => x == 'B') >= B && s.Count(x => x == 'A') >= A && s.Count(x => x == 'L') >= L && s.Count(x => x == 'O') >= O && s.Count(x => x == 'N') >= N) {
      ++count;
      s = s.ReplaceChar('B', B);
      s = s.ReplaceChar('A', A);
      s = s.ReplaceChar('L', L);
      s = s.ReplaceChar('O', O);
      s = s.ReplaceChar('N', N);
    }

    Console.WriteLine("Number of moves: " + count.ToString());
  }

  public static string ReplaceChar(this string s, char c, int i) {
    var regex = new Regex(Regex.Escape(c.ToString()));
    return regex.Replace(s, string.Empty, i);
  }
}

මේ රීප්ලේස් සීන් එකට රෙජෙක්ස් එකක් ලියාගත්තනම් මීට වඩා මේ වැඩේ කොලිටි

දැන් මෙතන තියෙන්නෙ, BALLON කියන වචනෙනෙ, ඉස්සරහට වෙන වචනයක් ආවොත්, ඒකටත් සෙට් වෙන්න ලියනවනම්, අදාල වචනෙ alphabetical character count එක <key,value> pair අරගෙන ඒක through ,loop කරලා ගත්තනම් හරි.

public static void generateAlphabiticalDict(string input)
{
    Dictionary<Char, int> alphabets = new Dictionary<Char, int>();

    for (int i = 0; i < input.Length; i++)
    {
        char character = input[i];
        if (Char.IsLetter(character))
        {
            if (alphabets.ContainsKey(character))
                alphabets[character] = alphabets[character] + 1;
            else
                alphabets.Add(character, 1);
        }
    }
}

 

[Stimulus mind]

bump

 

[Honda.putha]

psudocode eka nam liwwa.

bagayak liyaddi interesting wage.

code ekama gahala dannam

 

[HAneo]

psudocode eka nam liwwa.

bagayak liyaddi interesting wage.

code ekama gahala dannam

Thant's the spirit
poddak moleta exercise ekak denna karana eka watinawa

 

[spunkyisii]

Not related to me but i like these kind of stuff 🫠

 

[EnIgma001]

Bumpiyo

 

[Tharusha_Peiriss]

ඔයැයීලා lizard peoples ලා ද?...මොනාද ඒයී ඔය

 

[Solo Rider]

පාරෙ ඉන්නෙ
ගිහින් බලමු

 

[Anonymous_Abstract]

psudocode eka nam liwwa.

bagayak liyaddi interesting wage.

code ekama gahala dannam

dana eka poddak advance vidiyata dapan. Balloon valata characters one by one check karanne nethuwa

 

[u_make_me_sick_]

Java 8+, without any 3rd party libraries.
Meeta wada optimized widi godak ethi. eka paratama oluwata aawe meka.

import java.util.Arrays;
import java.util.Collections;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

public class EKTest {

  public int getMaxMoves(String string) {
    Map<String, Long> occurrences = Arrays.stream(string.split("")).collect(
        Collectors.groupingBy(s -> s, LinkedHashMap::new, Collectors.counting()));

    return Collections.min(List.of(
        (occurrences.get("B") != null ? occurrences.get("B").intValue() : 0),
        (occurrences.get("A") != null ? occurrences.get("A").intValue() : 0),
        (occurrences.get("L") != null ? (occurrences.get("L").intValue())/2: 0),
        (occurrences.get("O") != null ? (occurrences.get("O").intValue())/2: 0),
        (occurrences.get("N") != null ? (occurrences.get("N").intValue()) : 0)
        ));
  }

  public static void main(String [] args) {
    EKTest ek = new EKTest();
    System.out.println("Max Moves: " + ek.getMaxMoves("QAWABAWNL"));
    System.out.println("Max Moves: " + ek.getMaxMoves("BAONXXOLL"));
    System.out.println("Max Moves: " + ek.getMaxMoves("BAOOLLNNOLOLGBAXBBOOALLNN"));
  }
}

 

[helplesser]

රා කට්ටක් ගහලා පිසා කෑල්ලක් කකා අතල් එකේ හිටියේ.
කෑවා ආතල් මගුලක් දාලා

 

[HAneo]

රා කට්ටක් ගහලා පිසා කෑල්ලක් කකා අතල් එකේ හිටියේ.
කෑවා ආතල් මගුලක් දාලා

View attachment 180252

Code ekath dapan machan study karana unta help ekak weyi
And pls explain how you approached this. it's a learning curve

---

Java 8+, without any 3rd party libraries.
Meeta wada optimized widi godak ethi. eka paratama oluwata aawe meka.

import java.util.Arrays;
import java.util.Collections;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

public class EKTest {

  public int getMaxMoves(String string) {
    Map<String, Long> occurrences = Arrays.stream(string.split("")).collect(
        Collectors.groupingBy(s -> s, LinkedHashMap::new, Collectors.counting()));

    return Collections.min(List.of(
        (occurrences.get("B") != null ? occurrences.get("B").intValue() : 0),
        (occurrences.get("A") != null ? occurrences.get("A").intValue() : 0),
        (occurrences.get("L") != null ? (occurrences.get("L").intValue())/2: 0),
        (occurrences.get("O") != null ? (occurrences.get("O").intValue())/2: 0),
        (occurrences.get("N") != null ? (occurrences.get("N").intValue()) : 0)
        ));
  }

  public static void main(String [] args) {
    EKTest ek = new EKTest();
    System.out.println("Max Moves: " + ek.getMaxMoves("QAWABAWNL"));
    System.out.println("Max Moves: " + ek.getMaxMoves("BAONXXOLL"));
    System.out.println("Max Moves: " + ek.getMaxMoves("BAOOLLNNOLOLGBAXBBOOALLNN"));
  }
}

MAchan explain how you approached this as it will help to others
------ Post added on Jul 30, 2022 at 9:07 PM

 

[inspiron]

melo deyak terune na

 

[HAneo]

melo deyak terune na

Kisima kenekta oka mulin therenne na machan. ayi kiyawala balapan.
Brain Exercise ekak widihata try ekak dipan

 

[helplesser]

Code ekath dapan machan study karana unta help ekak weyi
And pls explain how you approached this. it's a learning curve

---

MAchan explain how you approached this as it will help to others
------ Post added on Jul 30, 2022 at 9:07 PM

They use words like balloon to trick you. Just understanding the real requirement will leads you to the right direction. This is what happens in the real world too. Business centric people use buzz words while explaining the requirements which is confusing. But as develpors we should able to filter the real thing from what they telling.

 

[BinDT]

letters=[]
x=input("word: ")
letters=list(x)
word=list("BALLOON")
round=0
number=0
set_no=1
n=1

    
while len(letters)!=n:
    while n<len(letters):
        if word[round] ==letters[n-1]:
            number=number+1
            
            
            if number==7:
                set_no=set_no+1
                round=0
                n=n+1
                
                
            else:
                n=n+1
                round=round+1
        else:
            n=n+1
  



print(set_no)

(samaharawita waradi athi.baninna epa hode. api thaama aadunikai programming walata)

 

[HAneo]

letters=[]
x=input("word: ")
letters=list(x)
word=list("BALLOON")
round=0
number=0
set_no=1
n=1

   
while len(letters)!=n:
    while n<len(letters):
        if word[round] ==letters[n-1]:
            number=number+1
           
           
            if number==7:
                set_no=set_no+1
                round=0
                n=n+1
               
               
            else:
                n=n+1
                round=round+1
        else:
            n=n+1
 



print(set_no)

(samaharawita waradi athi.baninna epa hode. api thaama aadunikai programming walata)

Hurray we have a python one.
a meka competition ekak neme machan.
just to polish our brain ne. uba meka python walin kala eka loku deyak. podi wistharekuth denna problem ekata enter un widiha

 

[baba-chuti]

uba dala tiyena image eka load wenne nane

 

[siri_ayya]

They use words like balloon to trick you. Just understanding the real requirement will leads you to the right direction. This is what happens in the real world too. Business centric people use buzz words while explaining the requirements which is confusing. But as develpors we should able to filter the real thing from what they telling.

මේකද approach ඒක