මෙ ගණන් හදන්නෙ කොහොමද? මෙ ගණන් හදන්නෙ කොහොමද?
Goldberg Member Dec 15, 2008 1,354 117 0 Sep 21, 2014 #1 මෙ ගණන් හදන්නෙ කොහොමද? මෙ ගණන් හදන්නෙ කොහොමද?
KingCM Well-known member Jul 23, 2013 6,920 948 113 www.biogen.lk Sep 21, 2014 #2 uktha karanna neda one.
Goldberg Member Dec 15, 2008 1,354 117 0 Sep 21, 2014 #3 KingCM said: uktha karanna neda one. Click to expand... yes uktha karanna oni
kinkon Well-known member Aug 5, 2007 115,928 2 115,994 113 Kandy ♕ පතිරූප දේස වාසෝ Sep 21, 2014 #4 Bump
MihiCherub Well-known member Sep 14, 2009 18,961 1 9,770 113 Gampaha Sep 21, 2014 #5 x = y / (Ry-1) F = 9C/5 +32 L = 2S/n - a Reactions: Goldberg
Sri_Sampath Well-known member Jan 26, 2010 14,737 12,764 113 Sep 21, 2014 #6 Goldberg said: මෙ ගණන් හදන්නෙ කොහොමද? Click to expand... ෆිසික්ස් පන්ති යන්න පටන් අරන් වාගේ
A. සිරියා Awrudu Games 2017 - Winners Aug 9, 2014 8,794 917 113 වැඩි ඈතක නෙමෙයි.. Sep 21, 2014 #7 1). R-(1/y) = (1/x) (Ry-1)/y = (1/x) y/(Ry-1) = x 2). 9C = 5(F-32) 9C/5 = F-32 (9C/5)+32 = F 3). 2S = n(a+l) 2S/n = a+l (2S/n)-a = l shapene neda Last edited: Sep 21, 2014 Reactions: Goldberg
1). R-(1/y) = (1/x) (Ry-1)/y = (1/x) y/(Ry-1) = x 2). 9C = 5(F-32) 9C/5 = F-32 (9C/5)+32 = F 3). 2S = n(a+l) 2S/n = a+l (2S/n)-a = l shapene neda
Goldberg Member Dec 15, 2008 1,354 117 0 Sep 21, 2014 #8 A. සිරියා;17163118 said: 1). R-(1/y) = (1/x) (Ry-1)/y = (1/x) y/(Ry-1) = x 2). 9C = 5(F-32) 9C/5 = F-32 (9C/5)+32 = F 3). 2S = n(a+l) 2S/n = a+l (2S/n)-a = l shapene neda Click to expand... Thanks rep 6
A. සිරියා;17163118 said: 1). R-(1/y) = (1/x) (Ry-1)/y = (1/x) y/(Ry-1) = x 2). 9C = 5(F-32) 9C/5 = F-32 (9C/5)+32 = F 3). 2S = n(a+l) 2S/n = a+l (2S/n)-a = l shapene neda Click to expand... Thanks rep 6
gangst3r.93 Member Sep 24, 2010 11,663 655 0 ගම්පහ Sep 21, 2014 #9 Owaye hadanna deyak nane.ekaine hoyanna thiyenne.ganakanam anith ewa denawane.nikan uththare ganna puluwan
Owaye hadanna deyak nane.ekaine hoyanna thiyenne.ganakanam anith ewa denawane.nikan uththare ganna puluwan