ABC is a right angled triangle. The circle with centre at D is drawn and AB & BC are tangents to it. The lengths of AB & AC are given above.
Calculate the small area in red, bounded by CA, CB & the arc of the circle.

I got this from a WhatsApp group.... Anyone interested should work out on their own.i saw solving this on a popular mathematics youtube channel, aaaand i don't remember it now![]()
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ABC is a right angled triangle. The circle with centre at D is drawn and AB & BC are tangents to it. The lengths of AB & AC are given above.
Calculate the small area in red, bounded by CA, CB & the arc of the circle.
Yes.. But do the calculation... It's interesting.1. calculate tan(B) and angle B
2. AD = AB.tan(B/2)
3. calculate DC.
4. if BC touches the circle at E, CDE triangle area can be calculated because we know DE (radius) and one angle.
5. calculate the area of the sector DCE using radius and angle B.
6 answer is 4 - 5
this is the value(√3/2) - π/4
Yes.. The hypotenuse BC turns out to be exactly 4 + 2 √3 and the angle ABC is 30 degrees.(√3/2) - π/4
mechchra marenne nathuwa ganna wena kramayk thiyanwda ? hypotenuse nm daannma ona une na..Yes.. The hypotenuse BC turns out to be exactly 4 + 2 √3 and the angle ABC is 30 degrees
This is the shortest...mechchra marenne nathuwa ganna wena kramayk thiyanwda ? hypotenuse nm daannma ona une na..
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