Take the case n=1 of x^n then it has 1 real solution
n= 2 the square root has 2 real solutions
n=3 the cube root has 1 real solution and 2 Complex solutions
As for your questio - The cube roots of 8 are 2, -1- i * SQR(3) and -1 + i* SQR(3)
When n=4 there are 2 real solutions and 2 complex solutions....
At higher n values there will be n solutions with one or two real (depending on whether n odd or even) and rest in the Complex plane.
Take the case n=1 of x^n then it has 1 real solution
n= 2 the square root has 2 real solutions
n=3 the cube root has 1 real solution and 2 Complex solutions
As for your questio - The cube roots of 8 are 2, -1- i * SQR(3) and -1 + i* SQR(3)
When n=4 there are 2 real solutions and 2 complex solutions....
At higher n values there will be n solutions with one or two real (depending on whether n odd or even) and rest in the Complex plane.