ඔන්න ඔතන තමා අවුල තියෙන්නෙ. බලල්ලු තුන් දෙනා එකතුවෙලා එක මීයෙක් අල්ලලා අනික් මීයා ගාවට යනව නම් ඕකේ. ඒත් එක බලලා එක මීයා ගානෙ අල්ලනවනම්. එතන ප්රශ්නයක් එනවා නේද
I had posted long ago on how to tackle work sharing/time based problems. The Cat problem is similar.
If 3 cats can catch 3 rats in 3 minutes, then
1 cat can catch 1 rat in the same 3 minutes.....
Hence
ONE cat can catch 1/3 of a rat per minute. So it follows that ONE cat can catch 100/3 rats in 100 minutes.
Thus
3 cats can catch
100 rats in 100 minutes.
As to the bicycles and the fly problem.... all these types of problems are NOT done by calculating distances and adding together. Though it will give the correct result, it's a tedious process adding a series of distances.
You need to look at the problem from a different perspective. You just calculate the time elapsed for the two cyclists to meet. They are heading towards each other at 10 km/h. That makes a relative velocity of 20 km/h and thus they would meet exactly in one hour., because the distance between them at the start was 20km.
Meanwhile, the fly keeps on flying in-between at 18 km/h. - Obviously in one hour it would have done 18 kms.
As for the Clutch/Brake problem, the answer is bit lengthy. Take a look at this video.
PS: No one responded yet to the problem I mentioned.
"
Which part of a train is moving backwards?" - (obviously we are talking about a train that's moving forwards)