මෙ ගණන් 2 හදන්නෙ කොහොමද?

[Karate]

මෙ ගණන් 2 හදන්නෙ කොහොමද?

මෙ ගණන් 2 හදන හැටි කියල දෙන්නකො

 

[joshmiller]

dan mathaka na , issara asawen haduwa mathakai

 

[බණ්ඩාර නිළමෙ]

Log2(4)*log3(27)
= log2(2^2)*log3(3^3)
=2log2(2)*3log3(3)
=2(1)*3(1)
=6

Loga(64)-loga(4)-loga(8)
=loga(2^6)-loga(2^2)-loga(2^3)
=6*loga(2)-2*loga(2)-3*loga(2)
=loga(2)

/* previously it was updated 64 = 2^8, now it's fixed*/

 

[s@dun193]

1)
log2^4 × log3^27
= log2^2^2 × log3^3^3
= 2 log2^2 × 3 log3^3
= 2 × 3
= 6



2)
log a^64 - log a4 - log a^8
= log a^ { 64÷(4×8)}
= log a^2

 

[coolmanaram]

dan mathaka na , issara asawen haduwa mathakai

hmm
how sad

​

 

[kmk]

log(2^4)*log(3^27)
={log(2*2(2))} * log(3*3(3))
=2{log(2*2)} * 3{log(3*3)} // because logb(x y) = y ∙ logb(x)
=2(1) *3(1)
=6.


log(a^64)-log(a^4)-log(a^8)
=log(a{64/(4*8)})

because logb(x / y) = logb(x) - logb(y),ekama padaya wenna ona(here it is base b)

=log(a^2) .