Maths Help

[mindscrew]

Machanla, OL maths wagayak mama ape mallita ugannanawa. Mama OL kale 1900 bara ganan wala nisa kisi deyak mathaka naha.

Me asamaanathaa gaana hadana hati poodak danna ekek kiyala denna puluwanda. OL AL kala kattiyata hari simple gaanak wenna athi.

X thama hoyanna ona. danna kenek gaana hadana steps tikath ekka uththare kiyala deepan, pin sidda wei.

thanks.

 

[cnf271]

machang mada vishala lakunada thiyenne??
samana lakuna nemaida??

 

[mindscrew]

machang madavishala lakunada thiyenne??
samana lakuna nemaida??

mada > lakuna thiyenne. asamaanatha (inequalities) kiyana wargaye gaanak machan.

 

[cnf271]

Machang man danna tharamin haras gunithaya dan nath baha mokada = lakunak nathi nisa but me krame balapan matath sure naha,,malligen ahanna harida kiyala!!

mama try kara bang!! but i cant ahh kohomada karanne!! machang mallige Achchu poth wala Exaples tikak balannako!!

 

[mindscrew]

Machang man danna tharamin haras gunithaya dan nath baha mokada = lakunak nathi nisa but me krame balapan matath sure naha,,malligen ahanna harida kiyala!!

mama try kara bang!! but i cant ahh kohomada karanne!! machang mallige Achchu poth wala Exaples tikak balannako!!

godak thanks machan try kalaata. rep+.
minihage achchu poth german walin thiyenne. ithin mata therenne naha ban.

 

[cnf271]

hm

godak thanks machan try kalaata. rep+.
minihage achchu poth german walin thiyenne. ithin mata therenne naha ban.

German??
malli local O/L nemida karanne???

 

[cnf271]

Uthare meka -3<x<3

!

 

[Rovin]

appaa mathaka nane

 

[Tom Riddle]

1/(x+3)>1/(x-3)

1/(x+3)-1/(x-3)>0

[(x-3)-(x+3)]/(x+3)(x-3)>0

-6/(x-3)(x+3) > 0

Dividing by -6 (division or multiplication by a negative value reverses the inequality)

1/(x-3)(x+3) < 0

For this to be true (x-3)(x+3)<0

So either x-3 is negative and x+3 is positive---------------(1)

OR

x+3 is positive and x-3 is negative---------------------(2)

(1)
x-3<0 AND x+3>0
x<3 AND x>-3

OR

(2)
x+3>0 AND x-3<0
x>-3 AND x<3

Both 1 and 2 give the same answer

therefore x>-3 AND x<3
which is -3<x<3

 

[බොරලු]

X=3 AND X-3 KIYANNE
X WALA DEKE BALAYA + Y WALA DEKE BALAYA
EKA WITHARAI MATHAKA

 

[Djtharindur]

1/(x+3)>1/(x-3)

1/(x+3)-1/(x-3)>0

[(x-3)-(x+3)]/(x+3)(x-3)>0

-6/(x-3)(x+3) > 0

Dividing by -6 (division or multiplication by a negative value reverses the inequality)

1/(x-3)(x+3) < 0

For this to be true (x-3)(x+3)<0

So either x-3 is negative and x+3 is positive---------------(1)

OR

x+3 is positive and x-3 is negative---------------------(2)

(1)
x-3<0 AND x+3>0
x<3 AND x>-3

OR

(2)
x+3>0 AND x-3<0
x>-3 AND x<3

Both 1 and 2 give the same answer

therefore x>-3 AND x<3
which is -3<x<3

TOM Uththre dila yalu...

 

[asela260]

Answer eka x < 3

 

[flag au:]

1/(x+3)>1/(x-3)

=
x-3-(x+3)/(x-3)(x+3)>0------------uda kapenawa


-6/(x+3)(x-3)>0

then we can write (using basic concept )
(-) nesa > change wenawa)
(x+3)(x-3)<0------basic concept

then answere is

-3<x<3 (u can draw it like this)
Number line:

 

[cnf271]

cool!! so u gt da answer!!

 

[mindscrew]

1/(x+3)>1/(x-3)

1/(x+3)-1/(x-3)>0

[(x-3)-(x+3)]/(x+3)(x-3)>0

-6/(x-3)(x+3) > 0

Dividing by -6 (division or multiplication by a negative value reverses the inequality)

1/(x-3)(x+3) < 0

For this to be true (x-3)(x+3)<0

So either x-3 is negative and x+3 is positive---------------(1)

OR

x+3 is positive and x-3 is negative---------------------(2)

(1)
x-3<0 AND x+3>0
x<3 AND x>-3

OR

(2)
x+3>0 AND x-3<0
x>-3 AND x<3

Both 1 and 2 give the same answer

therefore x>-3 AND x<3
which is -3<x<3

thanks very much for the help machan. much much appreciated.

can i just clarify one thing

to get from this -6/(x-3)(x+3) > 0 to this 1/(x-3)(x+3) < 0 did u multiply both sides by-1/6 ?

 

[mshassy]

1/(x+3) -1/(x-3)>0
=(x-3+x-3)/(x^2-9)>0
=-6(x^2-9)>0
=(x^2-9)<0
=(x-3)(x+3)<0
-3<x<3

 

[mindscrew]

1/(x+3) -1/(x-3)>0
=(x-3+x-3)/(x^2-9)
=-6(x^2-9)>0
=(x^2-9)<0
=(x-3)(x+3)<0
-3<x<3

=-6(x^2-9)>0 methana indan next step ekata =(x^2-9)<0 giye kohomada machan?

eka thama mata therenne naththe

 

[mindscrew]

cool!! so u gt da answer!!

got the answer machan. thanks very much bump dunnata machan.

 

[mshassy]

machan -6 depaththama bedapan ban! asamanathawayak - walin multiply weddi lakuna maaru karanna oni!

 

[mindscrew]

machan -6 depaththama bedapan ban! asamanathawayak - walin multiply weddi lakuna maaru karanna oni!

thanks a lot machan. loku udawwak rep+

appaa mathaka nane

X=3 AND X-3 KIYANNE
X WALA DEKE BALAYA + Y WALA DEKE BALAYA
EKA WITHARAI MATHAKA

Answer eka x < 3

TOM Uththre dila yalu...

1/(x+3)>1/(x-3)

=
x-3-(x+3)/(x-3)(x+3)>0------------uda kapenawa


-6/(x+3)(x-3)>0

then we can write (using basic concept )
(-) nesa > change wenawa)
(x+3)(x-3)<0------basic concept

then answere is

-3<x<3 (u can draw it like this)
Number line:

thanks everyone for the help. rep+